Linear Algebra Examples

$c = \frac{5}{9 (f - 32)}$

Step 1

Set the denominator in $\frac{5}{9 (f - 32)}$ equal to $0$ to find where the expression is undefined.

$9 (f - 32) = 0$

Step 2

Solve for $f$ .

Tap for more steps...

Step 2.1

Divide each term in $9 (f - 32) = 0$ by $9$ and simplify.

Tap for more steps...

Step 2.1.1

Divide each term in $9 (f - 32) = 0$ by $9$ .

$\frac{9 (f - 32)}{9} = \frac{0}{9}$

Step 2.1.2

Simplify the left side.

Tap for more steps...

Step 2.1.2.1

Cancel the common factor of $9$ .

Tap for more steps...

Step 2.1.2.1.1

Cancel the common factor.

$\frac{9 (f - 32)}{9} = \frac{0}{9}$

Step 2.1.2.1.2

Divide $f - 32$ by $1$ .

$f - 32 = \frac{0}{9}$

Step 2.1.3

Simplify the right side.

Tap for more steps...

Step 2.1.3.1

Divide $0$ by $9$ .

$f - 32 = 0$

Step 2.2

Add $32$ to both sides of the equation.

$f = 32$

Step 3

The domain is all values of $f$ that make the expression defined.

Interval Notation:

$(- \infty, 32) \cup (32, \infty)$

Set-Builder Notation:

${f | f \neq 32}$

Step 4